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Question

1- Using the equation below, how many grams of CO2 are produced when 54.5g of C2H2 is burned?

                               2C2H2 + 5O2 --> 4CO2 + 2H2O

2 - Use the following equation to determine how many grams of O2 are required to react with 22.50g of C7H16?

               C7H16 + 11O2 --> 7CO2 + 8H2O

Answer 1

1)

54.5g C₂H₂ x (1 mol / 26.04g) = 2.09 mol C₂H₂

2.09 mol C₂H₂ x (4 mol CO₂ / 2 mol C₂H₂) = 4.18 mol CO₂

4.18 mol CO₂ x (44.01g / 1 mol) = 183.96g CO₂

2)

22.50g C₇H₁₆ x (1 mol / 100.21g) = 0.22 mol C₇H₁₆

0.22 mol C₇H₁₆ (11 mol O₂ / 1 mol C₇H₁₆) = 2.24 mol O₂

2.24 mol O₂ x (15.99g/ 1 mol) = 35.82g O₂

Answer 2

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