help with chemistry plz

Question

1 -Calculate the molarity (M) of a solution that contains 1.5 grams of KOH and has a volume of 2.0 L.

2-How many grams of H2SO4 are needed to prepare 5.0 L of a 2 M H2SO4 solution?

Answer 1

1)

1.5g KOH x (1 mol KOH / 56.1g KOH) = 0.027 mol KOH

M = mol / L

M = 0.027 / 2.0

M = 0.0135

2)

M = mol / L

2 = mol / 5.0

2 (5.0) = mol

10 = mol

10 mol H₂SO₄ x (98.07g / 1 mol) = 980.7g H₂SO₄