phat1 = 267/4529
phat2 = 247/3312
phat = (267 + 247)/(4529 + 3312)
z-calc = (phat1 - phat2)/sqrt(phat(1-phat)(1/4529 + 1/3312))
p-value - P(|z| > z_calc)
reject null hypothesis is p-value < 0.05
confounding variable is candy consumption
Catalina L.
asked 05/07/21Rejection criteria: what is the p-value at which you will reject the null hypothesis?
test statistic: z value?
test statistic p value?
decision regarding the null hypothesis?
conclusion?
is this result practically significant, list two confounding variables?
A five year study of senior citizens compared to those who consumed sushi versus those who did not. It found that 267 out of 4529 candy consumers died from stomach cancer compared to 247 out of 3312 non-consumers.
conduct a significant tests at the 5% level of significance to determine if there is a significant difference in cancer rates of consumers versus non-consumers.
phat1 = 267/4529
phat2 = 247/3312
phat = (267 + 247)/(4529 + 3312)
z-calc = (phat1 - phat2)/sqrt(phat(1-phat)(1/4529 + 1/3312))
p-value - P(|z| > z_calc)
reject null hypothesis is p-value < 0.05
confounding variable is candy consumption
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