Todd W. answered 05/06/21
Recent College Graduate Specializing Biology Tutoring
1)
First we have to balance the equation:
4 P4O6 = P4 + 6P2O4
Then we have to convert moles of P4O6 (3.65 mol) to moles of P2O4 (?):
3.65 mol P4O6 x (6 mol P2O4 / 4 mol P4O6) = 5.48 mol P2O4
Answer:
5.48 moles of diphosphorus tetroxide are produced from 3.65 moles of tetraphosphorus hexoxide
2)
First we have to convert 50g of P2O4 into moles:
50g P2O4 x (1 mol / 125.96 g) = 0.4 mol P2O4
Then we have to convert moles of P2O4 to moles of P4O6:
0.4 mol P2O4 x (4 mol P4O6 /6 mol P2O4) = 0.27 mol P4O6
Answer:
0.27 moles of tetraphosphorus hexoxide are needed to produce 50 grams of diphosphorus tetroxide
3)
First we have to convert 18g of P4O6 into moles of P4O6:
18g P4O6 x (1 mol P4O6 / 219.88g P4O6) = 0.08 mol P4O6
Then we have to convert 0.08 mol P4O6 to moles of P2O4:
0.08 mol P4O6 x (6 mol P2O4 / 4 mol P4O6) = 0.12 mol P2O4
Then we convert moles of P2O4 into grams of P2O4:
0.12 mol P2O4 x (125.96g P2O4/ 1 mol P2O4) = 15.12 g P2O4
Answer:
15.12 grams of diphosphorus tetroxide are produced from 18 grams of tetraphosphorus hexoxide
*I hope this helps. I cannot promise the math is 100% correct here, but these are the steps you would follow for each part of this problem.