Hannah C.
asked 05/06/21Maclaurin Series (Not a test question)
Use the three non-zero terms of a Maclaurin series to estimate .
0.3107 | |
0.3102 | |
0.3100 | |
I chose this | 0.3103 |
1 Expert Answer
For the Maclaurin Series for f(x) = sin x, establish:
f(0) is sin 0 or 0;
f'(0) is cos 0 or 1;
f''(0) is -sin 0 or 0;
f'''(0) is -cos 0 or -1.
At f(iv), one obtains -(-sin 0) or 0, so the cycle {0, 1, 0, -1} repeats forever.
Then the Maclaurin Series for sin x is generated by ∑(from n = 0 to ∞)(-1)nx(2n + 1) ÷ (2n + 1)!,
which produces x − x3/3! + x5/5! − x7/7! + x9/9! − ...
Next write ∑(from n = 0 to ∞)(-1)nx(4n + 2) ÷ (2n + 1)! (with the power expression for x doubled)
in order to gain the generator for sin (x2).
Then sin (x2) is expanded as x2 − x6/3! + x10/5! − x14/7! + x18/9! − x22/11! + x26/13! − ...
This last is integrated term-by-term to
x3/3 − x7/(7•3!) + x11/(11•5!) − x15/(15•7!) + x19/(19•9!) − x23/(23•11!) + x27/(27•13!) − ...
A programmable calculator with a factorial capacity of 69! will sum this last expansion with x = 1
to 0.3102683017.
This same calculator will run a Riemann-Sum program with x incremented by 0.0001 for 10000
loops to 0.3103103762.
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Tom K.
Good choice. The Maclaurin result is 2867/9240, which rounds to this.05/10/21