For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g)

Question

For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g) the equilibrium concentrations were found to be [NH3]=0.250 M, [H2]=0.340 M, and [N2]=0.750 M. What is the equilibrium constant for this reaction? 𝐾c=

Answer 1

2NH₃(g) <==> 3H₂(g) + N₂(g)

0.250..............0.340......0.750.... Equilibrium concentrations (M)

Kc = [H₂]³[N₂] / [NH₃]² = (0.340)³(0.750) / (0.250)²

Kc = 0.02948 / 0.0625

Kc = 0.472