Chemistry Mole Calculations

Question

What is the volume in liters (at STP) of 6.02 x 10 (24.... avogadros number sorry cant make the 24 a tiny exponent) atoms of helium gas?

Answer 1

First you want to convert the atoms over into moles

6.02 x 10^24 atoms / (6.022 x 10^23 atoms/mol) = 10 mol

Then you want to convert Moles to Volume at STP

Volume = 10 mol x 22.4 L/mol = 224 L

meaning that the volume of 6.02 x 10^24 atoms of helium gas at STP is approximately 224 L

Answer 2

At STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 liters.

Find moles of gas and multiply by 22.4 liters/mol.

moles of gas = 6.02x10²⁴ atoms gas x 1 mol gas / 6.02x10²³ atoms = 10 moles of gas

10 moles of gas x 22.4 liters/mol = 224 liters of gas