Given the following overall reaction and half cell reactions, we can predict that, for the reaction as written

Question

Cl2(g) + 2Br- (aq) → 2Cl- (aq) + Br2(g)

Cl2(g) + 2e- → 2Cl- E° = 1.36 V

Br2(g) + 2e- → 2Br- E° = 1.09 V

what about Delta G

Answer 1

From the half cell reactions, and the provided Eº values, we can tell that the reaction as written will be spontaneous and will have a positive Eºcell of 1.36 - 1.09 = +0.27 V.

Because this is a spontaneous reaction, we can conclude that ∆G will be negative.