solve sin x - sin ^2x= 0 for all values of x

Answer 1

sinx - sin^2(x) = 0

sinx(1-sinx) =0, set each factor =0

sinx =0, x= pi + npi where n = any integer, or x=180 +180n where n = any integer. x= ...-360, -180, 0, 180, 360, ... or x= ...-2pi, -pi, 0, pi, 2pi, ...

1-sinx = 0, sinx=1, x= pi/2 + 2npi where n = any integer, or x=90 + 360n where n = any integer, x= ...-270, 90, 450, ... or x= ..-3pi/2, pi/2, 5pi/2, ...