sin(6x + 18) = cos(2x + 12)

Question

what is the value of x?

Answer 1

sin(6x + 18°) = cos(2x + 12°);

sin(6x + 18°) - sin(90°- 2x - 12°) = 0

sin(6x + 18°) + sin(2x - 78°) = 0

2sin(4x - 30°) cos(2x + 48°) = 0;

sin(4x - 30°) = 0; 4x - 30° = 180°n, x = 7.5° + 45°n, n = 0, ±1, ±2, ...

cos(2x + 48°) = 0; 2x + 48° = 90° + 180°n; x = 21° + 90°n, n = 0, ±1, ±2, ...

Answer 2

sin (6x + 18) = cos (2x + 12)

sin (6x + 18) = sin ((π / 2) - (2x + 12))

6x + 18 = (π / 2) - (2x + 12)

Can you solve for x and answer?