When 7.9 moles of [Co(NH3)5Cl]Cl2 is dissolved in water, how many moles of ions are in solution?

Question

When 7.9 moles of [Co(NH₃)₅Cl]Cl₂ is dissolved in water, how many moles of ions are in solution?

Answer 1

[Co(NH₃)₅Cl]Cl₂ when placed in water ionized to form [Co(NH₃)₅Cl]²⁺ + 2Cl^-

So, for each mole of the coordination complex, we obtain 3 moles of ions.

7.9 moles [Co(NH₃)₅Cl]Cl₂ x 3 moles ions / mole [Co(NH₃)₅Cl]Cl₂  = 23.7 moles of ions