
Afnan Z.
asked 05/03/21(cos^2x - sin^2x) / (cos^2x +sinxcosx)
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1 Expert Answer
Raymond B. answered 05/03/21
Tutor
5
(2)
Math, microeconomics or criminal justice
c^2 - s^2/ c^2- sc
(cos^2x - sin^2x)/(cos^2x - sinxcosx)
= (cosx-sinx)(cosx+sinx)/(cosx)(cosx - sinx)
= (cosx+sinx)/cosx
= 1+ sinx/cosx
= 1 + tanx
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Mark M.
What is your question?05/03/21