Li(s) + I2 (s) -->LiI(s) #1 Is the chemical equation above balanced? If not, then balance the chemical equation.

Question

2.What type of reaction(s) is/are being represented by the chemical reaction for the lithium iodine battery? 3. Is the reaction for the lithium iodine battery above an oxidation-reduction (redox) reaction?

4. If this is a redox reaction, then identify the following:What is undergoing oxidation (what is being oxidized)? Support your answer using oxidation numbers.

-What is undergoing reduction (what is being reduced)? Support your answer using oxidation numbers.

-What is the reducing agent?

-What is the oxidizing agent? .

I am confused on how to do all of this, i just started learning them but I am having huge complications on this problem.

Answer 1

(1). Li(s) + I2(s) ==> LiI is NOT balanced because you have 2 iodines on the left and only 1 on the right.

2Li(s) + 2I(s) ==> 2 LiI ... This is now balanced

(2). This is both a redox reaction and a synthesis reaction.

(3). Yes, it is a redox reaction.

(4). Li goes from oxidation number zero on the left to oxidation number 1+ on the right. Therefore it lost an electron so it was oxidized.

I goes from zero on the left to 1- on the right (oxidation numbers), so it has gained an electron and it was reduced.

Since Li was oxidized, it is the reducing agent.

Since I was reduced, it is the oxidizing agent.