J.R. S. answered 05/03/21
Ph.D. University Professor with 10+ years Tutoring Experience
copper(II) acetate = Cu(CH3COO)2
molar mass copper(II) acetate = 182 g/mol
20.3 g x 1 mol 1/ 182 g = 0.1115 mols Cu(CH3COO)2
367 g water x 1 kg / 1000 g = 0.367 kg
molality = mols/kg = 0.1115 mols / 0.367 kg = 0.304 m (3 sig. figs.)