Raymond B. answered 05/03/21
Tutor
5
(2)
Math, microeconomics or criminal justice
cos(theta) = adjacent side over hypotenuse = x/(sqr(x^2+y^2) = sqr19/(sqr(19+81) = sqr19/10
Angelo M.
asked 05/03/21Here is all that is given: cos Θ ; (√19,9)
Raymond B. answered 05/03/21
Math, microeconomics or criminal justice
cos(theta) = adjacent side over hypotenuse = x/(sqr(x^2+y^2) = sqr19/(sqr(19+81) = sqr19/10
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