Joel L. answered 05/02/21
Given equation of an ellipse:
(x−2)2/9+(y−5)2/36=1
The standard form you need is:
(x−h)2/b2+(y−k)2/a2=1
where:
a>b
2a= the length of the major axis (vertical)
2b= the length of the minor axis (horizontal)
(h,k) = center of ellipse
Therefore:
b2 = 9, a2=36
b = 3, a = 6
C(h,k) = (2,5)
The coordinates of the endpoints of the major axis are: (2,5±6)
The coordinates of the endpoints of the minor axis are: (2±3,5)
Highest point on the major axis: (2,11)
Lowest point on the major axis: (2,-1)
Rightmost point on the minor axis: (5,5)
Leftmost point on the minor axis: (-1,5)