How many liters of water vapor can be produced from 1.80 mol O2 at STP?

Question

The equation is: 2H2(g)+O2(g)=2H2O(g)

Answer 1

2H₂ + O₂ ==> 2H₂O

1.80 mol O₂ x 2 mol H₂O / 1 mol O₂ = 3.60 mol H₂O

At STP (standard temperature and pressure, 1 mole of ideal gas = 22.4 L)

3.60 mol H₂O(g) x 22.4 L / mol = 80.6 L