What volume will 0.375 mol of oxygen gas occupy at STP?

Answer 1

The volume of any ideal gas at STP (standard temperature and pressure) is 22.4 L.

Therefore...

0.375 moles x 22.4 L / mole = 8.4 L

Answer 2

Density of oxygen is 1.429 g / l at STP

Atomic mass of O is about 16, so molecular mass of O₂ = 32

So 0.375 moles is 0.375 x 32 g

From density liters = ( 0.375 x 32 / 1.429) = 8.39748 l

As 0.375 has 3 significant figures, state your answer to 3 significant figures ie 8.40 l