J.R. S. answered 04/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
just plug in the values and solve for C.
3.6 kJ = (0.64 kg)(C)(24º)
C = 3.6 kJ / (0.64 kg)(24º) = answer in kJ/kg/degree
Madison M.
asked 04/29/21A chemist carefully measures the amount of heat needed to raise the temperature of a 0.64kg sample of a pure substance from −5.4°C to 18.6°C. The experiment shows that 3.6kJ of heat are needed. What can the chemist report for the specific heat capacity of the substance? Round your answer to 2 significant digits.
J.R. S. answered 04/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
just plug in the values and solve for C.
3.6 kJ = (0.64 kg)(C)(24º)
C = 3.6 kJ / (0.64 kg)(24º) = answer in kJ/kg/degree
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