J.R. S. answered 04/29/21
Ph.D. University Professor with 10+ years Tutoring Experience
Oxidation reaction:
Mn(s) ==> Mn2+ + 2e- Eºoxid = 1.19 V
Reduction reaction:
Zn2+ + 2e- ==> Zn(s) Eºred = -0.76
Eºcell = 1.19 - 0.76 = 0.43 V
∆Gº = -nFEºcell
n = # electrons = 2
F = Faraday const. = 96,485 C/mol e-
E = 0.43 V
∆Gº = -(2)(96,485)(0.43)
∆Gº = -41,487 J/mol = -41.5 kJ/mol