How many mL of 0.500 M NaI would be required to make a 0.0350 M solution of NaI when diluted to 275.0 mL with water?

Answer 1

V1 M1 = V2M2

(V1 ml)(0.500 M) = (275 ml)(0.0350 M)

V1 = (275 ml)(0.0350 M) / 0.500 M

V1 = 19.25 mls = 19.3 mls (3 sif. figs.) would be required