How many mL of 0.100 M NaCl would be required to make a 0.0355 M solution of NaCl when diluted to 150.0 mL with water?

Answer 1

V1M1 = V2M2

(V1 ml)(0.100 M) = (150 ml)(0.0355 M)

V1 = (150)(0.0355) / 0.100

V1 = 53.3 mls (3 sig. figs.) are required