J.R. S. answered 04/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
Write the balanced equation for the titration:
2HClO4 + Ca(OH)2 ==> Ca(ClO4)2 + 2H2O
moles Ca(OH)2 used = 0.110 mol / L x 0.0242 L = 0.00266 moles Ca(OH)2 used
moles HClO4 present = 0.00266 mol Ca(OH)2 x 2 mol HClO4 / 1 mol Ca(OH)2 = 0.00532 mols HClO4 present
This is in 24.3 = 0.0243 L, so concentration of HClO4 is 0.00532 mols / 0.0243 L = 0.219 M