Determine K for a reaction at 200 K if ∆G° =19.7 kJ/mol. (R = 8.314 J/mol ･ K)

Answer 1

∆Gº = -RT ln K

19.7 kJ/mol = -(0.008314 kJ/K-mol)(200 K) ln K

ln K = -11.85

K = 7.14x10^-6