Raymond B. answered 06/25/25
Math, microeconomics or criminal justice
k-18, j-18/3, k-18 = 2(j-6) = 2j-12, k-2j = 6
j-6 = 2+6 = 8, j=14 = Jace at first
k=2j+6 =2(14)+6 = 28+6 = 34 = kamden at first
(j,k) = (14,34)
kamden gave 18 away leaving 34-18 = 16 left. Jace gave 6 away leaving 14-6 = 8 left
Jace had 2 more than he gave away 8=2+6