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Question

In ΔPQR, the measure of ∠R=90°, QP = 73, PR = 48, and RQ = 55. What ratio represents the sine of ∠Q?

Answer 1

REMEMBER: SOH - CAH - TOA Sine Cosine Tangent

Opposite Adjacent Opposite

Hypotenuse Hypotenuse Adjacent

Simply draw the triangle and make sure to label it accurately.

Now, what is the Sine of ∠Q? Sine = SOH = Opposite/Hypotenuse

So, the Sine of ∠Q or: Sin ∠Q = opp/hyp = 48/73

Answer 2

The sine of an angle Q is defined as:

sin Q = opposite leg / hypotenuse = PR/QP