Write the equation of a line that passes through point (-5,3) and is perpendicular to y=3⁄5 x +2.

Answer 1

Hi Lia! Here's some advice to help you get started.

Our goal is to write the perpendicular line's equation in the form y=mx+b. To do so, we need to use the given information to find the slope (m) and the y-intercept (b).

The perpendicular line's slope will be the negative reciprocal of the original function's slope. In this case, the original function's slope is 3/5. The reciprocal is -5/3 (we just flip the fraction upside down and change the sign). At this point, we know that the perpendicular line's equation is of the form y=(-5/3)x+b. To find the b-value, plug in the point (-5,3) into the perpendicular line's equation.

I hope this helps, but let me know if you would like more help on this problem.