How many moles of H 3 PO 4 are produced when 82.2 g P4010 reacts completely to form H 3 PO 4 ?P 4 O 10 (s)+6H 2 O(l) 4H 3 PO 4 (aq) Answer in standard notation to two decimal places.

Question

How many moles of H 3 PO 4 are produced when 82.2 g P4010 reacts completely to form H 3 PO 4 ?

P 4 O 10 (s)+6H 2 O(l) 4H 3 PO 4 (aq)

Answer in standard notation to two decimal places.

Answer 1

P₄O₁₀ + 6H₂O ==> 4H₃PO₄ ... balanced equation

Use stoichiometry and dimensional analysis to solve the problem:

molar mass P₄O₁₀ = 284 g/mol

82.2 g P₄O₁₀ x 1 mol P₄O₁₀ / 284 g x 4 mols H₃PO₄ / 1 mol P₄O₁₀ = 1.16 mols H₃PO₄