J.R. S. answered 04/23/21
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
2 NaN3 --> 2Na + 3N2 ... this is the balance equation
65.1 g N2 x 1 mol N2 / 28 g x 2 mol NaN3 / 3 mol N2 x 65 g / mol NaN3 = 101 g NaN3