Given the following reaction and its equilibrium constant at a certain temperature...

Question

Given the following reaction and its equilibrium constant at a certain temperature:

N₂(g) + 3H₂(g) ↔ 2NH₃(g)         K_c = 2.67

Calculate the numerical value of the equilibrium constant for the following reaction at the same temperature.

2NH₃(g) ↔ N₂(g) + 3H₂(g)

Answer 1

N₂(g) + 3H₂(g) <==> 2NH₃(g)         K_c = 2.67

2NH₃(g) <==> N₂(g) + 3H₂(g) This is the reverse reaction of the one given above. In this case, to find the K value, we simply take the inverse of the original K value. Thus, Kc = 1/2.67 = 0.375