The temperature of a sample of water increases from 20°C to 46.6°C as it absorbs 5650 J of heat. What is the mass of the substance? The specific heat of water is 4.186 J/gºC.

Question

The temperature of a sample of water increases from 20°C to 46.6°C as it absorbs 5650 J of heat. What is the mass of the substance? The specific heat of water is 4.186 J/gºC. Show all work and round your answer to the hundredths place. 

Answer 1

q = mC∆T

q = heat = 5650 J

m = mass = ?

C = specific heat = 4.186 J/gº

∆T = change in temperature = 46.6 - 20 = 26.6º

Solving for m, we have..

m = q / C∆T = 5650 J / (4.186 J/gº)(26.6º)

m = 50.7 g