What is the [OH-1] concentration if the pH is 11.32?

Question

1.) 2.68 x 10^-4

2.) 0.0021 M

3.) 4.79 x 10^-9 M

4.) 1 x 10^-14 M

5.) 7.00 x 10^-14 M

Answer 1

14=pH+pOH

pOH=14-11.32

pOH=2.68

[OH-]=10^-pOH=10-2.68=0.002089