J.R. S. answered 04/22/21
Ph.D. University Professor with 10+ years Tutoring Experience
1). The other product is sodium chloride (NaCl)
2). CaCl2(aq) + Na2CO3(s) ==> CaCO3(s) + 2NaCl(aq) ... balanced equation
3). 10 g CaCO3 x 1 mol CaCO3/100 g = 0.1 mole CaCO3
0.1 mol CaCO3 x 1 mol CaCl2/mol CaCO3 = 0.1 mol CaCl2 needed
(x L)(0.5 mol/L) = 0.1 mol and x = 0.2 L = 200 ml CaCl2 needed
4). 0.1 mol CaCO3 x mol Na2CO3/mol CaCO3 x 106 g Na2CO3/mol = 10.6 g Na2CO3