The rate constant for the decay of a radioactive element is 1.48 × 10⁻³ day⁻¹. What is the half-life of this element?

Answer 1

We'll assume the decay is first order, as is the case for radioactive decay. For a 1st order reaction, the half life (t_1/2) = 0.693/k

(t_1/2) = 0.693 / 1.48x10^-3 day-1

(t_1/2) = 4.68x10² days = 468 days