Tom K. answered 04/20/21
Knowledgeable and Friendly Math and Statistics Tutor
This problem is trivial to solve. cos x and cos 2x have maximum values of 1, and both are required in order for
2 cos 2x + 4 cos x = 6
cos x = 1 only once on [0, 2 pi), at 0, and cos 2x = 1 there as well.
Thus, the only solution on [0, 2pi) is 0.
Even if the first term was (cos (x))^2, we would have the same result.
Tom K.
0. 0 is in the interval[0, 2 pi) and solves the problem04/20/21
Kendra K.
Would the answer be 0 or No solution?04/20/21