J.R. S. answered 04/20/21
Ph.D. University Professor with 10+ years Tutoring Experience
XY₃ + A₂ → XA + Y2A ... unbalanced
4XY₃ + 5A₂ → 4XA + 6Y2A ... balanced equation
b) 2.45 mol XA x 5 mol A2 / 4 mol XA = 3.06 mol A2
Chris W.
asked 04/20/21In the reaction below, how many moles of A2 will be used to produced 2.45 mol of XA?
a. Balance the chemical equation: XY₃ + A₂ → XA + Y2A
b. moles A2
J.R. S. answered 04/20/21
Ph.D. University Professor with 10+ years Tutoring Experience
XY₃ + A₂ → XA + Y2A ... unbalanced
4XY₃ + 5A₂ → 4XA + 6Y2A ... balanced equation
b) 2.45 mol XA x 5 mol A2 / 4 mol XA = 3.06 mol A2
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