What are the boiling point and freezing point of a 0.488 m aqueous solution of any nonvolatile, nonelectrolyte solute?

Question

What are the boiling point and freezing point of a 0.488 m aqueous solution of any nonvolatile, nonelectrolyte solute?

Answer 1

Colligative properties:

Boiling point elevation and freezing point depression.

∆T = imK

∆T = change in freezing or boiling point = ?

i = van't Hoff factor = 1 for a non volatile non electrolyte

m = molality = moles solute/kg solvent = 0.488

K = freezing or boiling constant for water = 1.86º/m and 0.512º/m for freezing and boiling constant, respectively.

Plug in the values and solve for ∆T. Add that value to 100ºC to get the new boiling point and subtract that value from 0ºC to get the new freezing point.