Suppose you need to prepare 135.9 mL of a 0.299 M aqueous solution of NaCl. What mass, in grams, of NaCl do you need to use to make the solution?

Answer 1

1 l contains 0.299 moles

135.9 ml contains (135.9 / 1000) x 0.299 moles

Find the molecular mass of NaCl in g , and multiply that by this number of moles

Answer 2

Use dimensional analysis and a molar mass of NaCl of 58.4 g/mol

135.9 ml x 1 L/1000 ml x 0.299 mol / L x 58.4 g NaCl / mol = 2.37 g NaCl