J.R. S. answered 04/19/21
Ph.D. University Professor with 10+ years Tutoring Experience
I agree with all of your answers.
For the third question, I got 660 g of propane, which is not one of the choices.
Jesset C.
asked 04/19/21For the following questions, use the following: A gas grill burns Propane (C3H8) in the presence of more than sufficient Oxygen (O2). This reaction produces water vapor and Carbon Dioxide. The temperature and pressure conditions are such that 1 mole of each gas occupies 1 liter of volume.
* What is the balanced equation for this reaction?
A. C3H8 + 4O2 → 2CO2 + 4H2O
B. C3H8 + 5O2 → 3CO2 + 4H2O
C. 2C3H8 + 6O2 → 6CO2 + 8H2O
D. 2C3H8 + 5O2 → 6CO2 + 4H2O
E. None of the Above
* If 15 liters of Propane are completely consumed, how many liters of water vapor will be produced?
A. 7.5 L H2O (g)
B. 15 L H2O (g)
C. 30 L H2O (g)
D. 45 L H2O (g)
E. 60 L H2O (g)
* If 15.00 liters of Propane are completely consumed, how many grams of Propane were there?
A. 40.08 g Propane
B. 80.16 g Propane
C. 160.32 g Propane
D. 320.64 g Propane
E. None of the Above
* If 15.00 liters of Propane are completely consumed, how many grams of Carbon Dioxide are produced?
A. 15 L CO2
B. 45 L CO2
C. 660. g CO2
D. 1980. g CO2
E. 1.98 × 105 g CO2
J.R. S. answered 04/19/21
Ph.D. University Professor with 10+ years Tutoring Experience
I agree with all of your answers.
For the third question, I got 660 g of propane, which is not one of the choices.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.