J.R. S. answered 04/19/21
Ph.D. University Professor with 10+ years Tutoring Experience
Na2S2O3 + Cl2 + H2O → NaHSO4 + HCl ... unbalanced equation.
Of course, we must balance this redox equation before answering the questions.
S2O32- +5H2O ==> 2HSO4- + 8H+ + 8e- oxidation half reaction
Cl2 + 2e- ==> 2Cl- [x4] reduction half reaction
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S2O32- +5H2O + 4Cl2 + 8e- ==> 2HSO4- + 8H+ + 8e- + 8Cl-
Na2S2O3 + 4Cl2 + 5H2O ==> 2NaHSO4 + 8HCl ... balanced equation
How many moles of Na2S2O3 are needed to react with 0.40 moles of Cl2?
0.4 mol Cl2 x 1 mol Na2S2O3 / 4 mol Cl2 = 0.10 moles (ANSWER A)
How many moles of HCl can be formed from 0.25 moles of Cl2?
0. 25 mol Cl2 x 8 mol HCl / 4 mol Cl2 = 0.5 moles HCl (ANSWER E)
How many moles of H2O react if 0.48 moles of HCl is formed?
0.48 mol HCl x 5 mol H2O /8 mol HCl = 0.3 moles H2O (ANSWER C)
Hope this all makes sense to you.