Given the function g(x) = x^2 + 2x, evaluate [g(x) − g(a)] /[x − a ], x ≠ a

Answer 1

(x^2+2x-(a^2+2a))/(x-a) =

((x^2-a^2)+(2x-2a))/(x-a=

((x-a)(x+a)+2(x-a))/(x-a) =

((x-a)(x+a+2))/(x-a) = as x is not equal to a,

x+a+2