J.R. S. answered  04/17/21
Ph.D. University Professor with 10+ years Tutoring Experience
SO2(s) ==> SO2(g)
Step 1: melt SO2(s) at -73ºC:
q = m∆Hf = (4.250 kg)(1 mol/0.096 kg) x 8.619 kJ/mol = 381.57 kJ
Step 2: Raise temp of SO2(l) from - 73º to -10º
q = mC∆T = (4250 g)(0.995 J/gº)(63º) = 266,411 J = 266.411 kJ
Step 3: Convert SO2(l) to a gas @ -10º
q = m∆Hvap = (4.250 kg)(1 mol/0.096 kg)(25.73 kJ/mol) = 1139 kJ
Step 4: Raise temp of SO2(g) from -10º to 60º
q = mC∆T = (4250 g)(0.622 J/gº)(70) = 185,045 J = 185.045 kJ
Sum the q values:
381.57 kJ + 266.41 kJ + 1139 kJ + 185.05 kJ = 1972 kJ = heat required