OC is a radius and AB is a diameter, so AB = 2 * 9 = 18
OB is a radius so it also equals 9
BC is the hypotenuse of a right triangle with legs equal to 9 (a 45-45-90 right triangle) so hypotenuse is sqrt(2) times 9.
Alyssa Z.
asked 04/16/21Consider the following figure.
A circle has center point O. There are 3 points on the circle and 3 interior line segments.
Given: In ⊙O, OC ⊥ AB and OC = 9.
Find the following.
(a) AB
(b) BC
OC is a radius and AB is a diameter, so AB = 2 * 9 = 18
OB is a radius so it also equals 9
BC is the hypotenuse of a right triangle with legs equal to 9 (a 45-45-90 right triangle) so hypotenuse is sqrt(2) times 9.
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