How many moles of KOH are needed to neutralize 1.5 moles of sulfuric acid?

Answer 1

This comes down to stoichiometry. KOH and H2SO4 are your reactants. H2SO4 has 2 protons per unit so it'll take 2 KOH per H2SO4.

The balanced reaction is as written.

2 KOH + H2SO4 ---> 2 H2O + K2SO4.

So if we have 1.5 moles of H2SO4 we need

1.5 moles H2SO4 ( 2 KOH/1 H2SO4) = 3 moles of KOH.