J.R. S. answered 04/16/21
Ph.D. University Professor with 10+ years Tutoring Experience
First, use the Ksp to calculate the molar solubility of CuCO3.
CuCO3(s) <==> Cu2+(aq) + CO32-(aq)
Ksp = 2.5x10-10 = [Cu2+][CO32-]
2.5x10-10 = (x)(x) = x2
x = 1.58x10-5 M = molar solubility of CuCO3
Next we find how many moles of CuCO3 is contained in 3.0 g, using a molar mass of 123.6 g/mol
3.00 g x 1 mol/123.6 g = 0.0243 moles
Finally, we calculate volume of water to dissolve 0.0243 moles to give a concentration of 1.58x10-5 M:
0.0243 mol / x L = 1.58x10-5 mol/L
x = 1.5x103 L of water (2 sig.figs.) needed to dissolve 3.0 g of CuCO3