Mark M. answered 04/14/21
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
ex = 1 + x + x2/2! + x3/3! + ...
So, e-x^2 = 1 + (-x2) + (-x2)2/2! + ... = 1 - x2 + x4/2 - ...
Therefore, ∫(from 0 to 1) e-x^2dx = ∫(from 0 to 1) [ 1 - x2 + x4/2 -...]dx = x - x3/3 + x5/10 - ...(from 0 to 1)
≈ 1 - 1/3 + 1/10 = 0.76666666 ≈ 0.767