if each edge of the base of a regular hexagonal prism is doubled but the height stays the same, how does the volume change?

Answer 1

Consider the formula volume:V=[(3√3)/2]a²h where a is the length of the side of the base, if a doubles, i.e. 2a,

(2a)² = 4a², so the volume is quadrupled...

Answer 2

Volume of prism = area of base * height.

If edge of hexagonal base is doubled, the area of the base is doubled, so the volume of the prism is doubled.