<DAB = <DBA
<DAC = <DBC
<DAB + <DAC = <DBA + <DBC addition property of equality
<DAB + <DAC = <CAB angle addition
<DB A + <DBC = <CBA
<CAB = <CBA transitive property
0000 1.
asked • 04/14/21Prove the Following:
Given: ∠DAB < ∠DBA, ∠DAC < ∠DBC
Prove: ∠CAB < ∠CBA
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