Raymond B. answered 04/14/21
Math, microeconomics or criminal justice
24 is the initial velocity. 24t is the distance traveled at time t. at t=0 it didn't go anywhere. time t = 1 it traveled 24 feet but minus the effect of gravity, the t^2 term.
A) 24 feet per second is the initial velocity
B) 8 feet is the initial height
C) time in the air is found by setting h=0 and solving for t
-16t^2 +24t + 8 = 0
2t^2 -3t -1 = 0
try to factor, it doesn't factor, but almost which suggests a possible sign typo in the problem, but accepting it as given
t= 3/4 + sqr(9+8) = 3/4+sqr17 = 4.873 seconds in the air
D) max height is found by setting the derivative = 0, which leads to t=3/4
plug 3/4 into the original equation to get h=-16(3/4)^2 + 24(3/4) + 8= 17 feet for maximum height. It reached max height of 17 feet after 3/4 of a second