Complete and balance the following half-reaction in basic solution

Question

Cr(OH)3(s) -> CrO4^2-(aq)

Answer 1

Cr(OH)₃ ==> CrO₄^2- ... unbalanced

Cr(OH)₃ + H₂O ==> CrO₄^2- ... balanced for oxygens

Cr(OH)₃ + H₂O + 5OH^- ==> CrO₄^2- + 5H₂O ... balanced for oxygens and hydrogens using base OH-

Cr(OH)₃ + H₂O + 5OH^- ==> CrO₄^2- + 5H₂O + 3e- ... balanced for O, H and charge = balanced equation